Pytanie 14
In reactions A+B---(k1)--->C 2C---(k2)--->D k2>>k1 Therefore:
d[D]/dt =~ (k1k2)/(k1+k2) * [A][B]
[D] =~ (k2)/(2k1) * [C]
the steady-state approx. cannot be used for [B]
the steady-state approx. can be used for [C]
rate of formation of [D] is approx. first order in [A]